x^2(x+2)-2x(x+2)-3(x+2)=0

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Solution for x^2(x+2)-2x(x+2)-3(x+2)=0 equation: 


Simplifying
x2(x + 2) + -2x(x + 2) + -3(x + 2) = 0

Reorder the terms:
x2(2 + x) + -2x(x + 2) + -3(x + 2) = 0
(2 * x2 + x * x2) + -2x(x + 2) + -3(x + 2) = 0
(2x2 + x3) + -2x(x + 2) + -3(x + 2) = 0

Reorder the terms:
2x2 + x3 + -2x(2 + x) + -3(x + 2) = 0
2x2 + x3 + (2 * -2x + x * -2x) + -3(x + 2) = 0
2x2 + x3 + (-4x + -2x2) + -3(x + 2) = 0

Reorder the terms:
2x2 + x3 + -4x + -2x2 + -3(2 + x) = 0
2x2 + x3 + -4x + -2x2 + (2 * -3 + x * -3) = 0
2x2 + x3 + -4x + -2x2 + (-6 + -3x) = 0

Reorder the terms:
-6 + -4x + -3x + 2x2 + -2x2 + x3 = 0

Combine like terms: -4x + -3x = -7x
-6 + -7x + 2x2 + -2x2 + x3 = 0

Combine like terms: 2x2 + -2x2 = 0
-6 + -7x + 0 + x3 = 0
-6 + -7x + x3 = 0

Solving
-6 + -7x + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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